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Byju's Answer
Standard VIII
Mathematics
Factorisation by Common Factors
Linked Compre...
Question
Linked Comprehensive type
A
=
5
x
2
−
16
x
−
21
B
=
3
(
x
+
2
)
2
−
5
(
x
+
2
)
+
2
Factors of
A
are
A
(
x
+
1
)
(
5
x
−
21
)
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B
(
x
−
1
)
(
5
x
−
21
)
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C
(
x
+
1
)
(
5
x
+
21
)
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D
(
x
−
1
)
(
5
x
+
21
)
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Solution
The correct option is
C
(
x
+
1
)
(
5
x
−
21
)
A
=
5
x
2
−
116
x
−
21
B
=
3
(
x
+
2
)
2
−
5
(
x
+
2
)
+
2
factor of A.
5
x
2
−
16
x
−
21
⇒
5
x
2
−
21
x
+
5
x
−
21
⇒
x
(
5
x
−
21
)
+
1
(
5
x
−
21
)
⇒
(
5
x
−
21
)
(
x
+
1
)
Suggest Corrections
0
Similar questions
Q.
Linked Comprehensive type
A
=
5
x
2
−
16
x
−
21
B
=
3
(
x
+
2
)
2
−
5
(
x
+
2
)
+
2
Factors of
B
are
Q.
Linked Comprehensive type
A
=
5
x
2
−
16
x
−
21
B
=
3
(
x
+
2
)
2
−
5
(
x
+
2
)
+
2
Sum of the factors of
A
and
B
are
Q.
The factor of
5
x
2
−
15
x
−
7
x
+
21
is
Q.
Find the value of
(
x
−
y
)
, if
15
x
+
17
y
=
21
and
17
x
+
15
y
=
11
.
Q.
15
x
+
17
y
=
21
and
17
x
+
15
y
=
11
then. What is the value of
x
+
y
?
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