Question

List I and List II contain four entries each. Entries of List I are to be matched with entries of List II. One or more than one entries of List I may match with the same entry of List II.

Answer 1

Phenol undergoes Reimer Tiemann's reaction.

In Reimer Tiemann's reaction, the reaction of phenol with alkaline chloroform forms salicylaldehyde (or hydroxy benzaldehyde).

Phenol is more acidic than water. (due to resonance stablisation of phenoxide ion).

Hence, phenol is a weak acid and water is neutral.

$2,4,6$-Trinitrophenol will react with sodium bicarbonate to form the sodium salt of $2,4,6$-Trinitrophenol.

$2,4,6$-Trinitrophenol is more acidic than water.

$2,4,6$-Trinitrophenol is a weak acid (due to resonance stabilization of phenoxide ion and due to the presence of three strong electron-withdrawing nitro groups) and water is neutral.

Ethanol will give a positive iodoform test.

Iodine, in alkaline medium, oxidizes ethanol to acetaldehyde which contains $C{H}_{3}CO$ group.

Due to the presence of $C{H}_{3}CO$ group,

Iodoform reaction is possible.

Sodium acetate $C{H}_{3}COONa$ and iodoform $CH{I}_3$ are the end products.

Benzoic acid will react with sodium bicarbonate to form sodium benzoate.

The reaction is as follows:

$PhCOOH+NaHC{O}_3\to PhCOONa+H_{2}O+C{O}_2\uparrow$

Benzoic acid will be more acidic than water as benzoate ion is resonance stabilized.

.

Hence, the correct answer is $A-3,4,B-2,4,C-1$ and $D-2,4$.