List-I has compounds and list-II has oxidation state of $S$ in these compounds. The correct match is:
List-I List-ll
A $) H_{2} S O_{4}$ 1 $) + 4$
B $) H_{2} S_{2} O_{6}$ 2 $) + 3$
C $) H_{2} S O_{3}$ 3 $) + 2$
D $) H_{2} S_{2} O_{4}$ 4 $) + 6$

5 $) + 5$

A-4, B-5, C-2, D-1

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A-3, B-4, C-1, D-2

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A-4, B-5, C-1, D-2

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A-2, B-5, C-1, D-3

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Solution

The correct option is D A-4, B-5, C-1, D-2
$H_{2} S O_{4} = + 6$
$H_{2} S_{2} O_{6} = + 5$
$H_{2} S O_{3} = + 4$
$H_{2} S_{2} O_{4} = + 3$

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Similar questions

Match List I with List II and select the correct answer using the codes given below the lists

List I (Compound) List II (Oxidation state of N)

(A) $N O_{2}$ (1) +5

(B) $H N O$ (2) -3

(D) $N_{2} O_{5}$ (4) +1

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Match List I with List II and select the correct answer using the codes given below the lists

List I (Compound) List II (Oxidation state of N)

(A) $N O_{2}$ (1) +5

(B) $H N O$ (2) -3

(D) $N_{2} O_{5}$ (4) +1

\begin{matrix} L i s t I & L i s t I I (a) B a c i l l u s t h u r i n g i e n s i s & 1. P r o d u c t i o n o f c h i t i n a s e s (b) R h i z o b i u m & 2. S c a v e n g i n g o f o i l s p i l l s (c) E s c h e r i c h i a c o l i & 3. I n c o r p o r a t i o n o f^{'} n i f^{'} g e n e (d) P s e u d o m o n a s & 4. p r o d u c t i o n o f B t t o x i n (e) T r i c h o d e r m a & 5. P r o d u c t i o n o f h u m a n i n s u l i n \end{matrix}

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