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Question


ln ΔABC, If SinASinC=Sin(AB)Sin(BC) then a2, b2, c2 are in

A
A.P.
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B
G.P.
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C
H.P.
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D
A.G.P.
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Solution

The correct option is A A.P.
2sinAsin(BC)=2sin(AB)sinC
cos(AB+C)cos(A+BC)=cos(ABC)cos(AB+C)
2cos(A+CB)=cos(A(B+C))+cos(A+BC)
2cos2B=cos2A+cos2C
24sin2B=12sin2A+12sin2C
2sin2B=sin2A+sin2C
2b2=a2+c2
a2,b2,c2 are in A.P.

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