lnΔABC,IfSinASinC=Sin(A−B)Sin(B−C) then a2,b2,c2 are in
A
A.P.
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B
G.P.
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C
H.P.
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D
A.G.P.
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Solution
The correct option is A A.P. 2sinAsin(B−C)=2sin(A−B)sinC cos(A−B+C)−cos(A+B−C)=cos(A−B−C)−cos(A−B+C) 2cos(A+C−B)=cos(A−(B+C))+cos(A+B−C) 2cos2B=cos2A+cos2C 2−4sin2B=1−2sin2A+1−2sin2C 2sin2B=sin2A+sin2C 2b2=a2+c2 ∴a2,b2,c2areinA.P.