Log Kp-Kc - log RT - 0 is a relationship for the reaction-

The correct option is B 2SO_2(g) + O_2(g) ⇌ 2SO_3(g) log K_p/K_c + log RT = 0 logK_P=logK_C log(RT) Taking Anti log we get, K_P=K_C( ...

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Types of Equillibrium

log Kp/Kc + l...

Question

$l o g \frac{K_{p}}{K_{c}} + l o g R T = 0$ is a relationship for the reaction:

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

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2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

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H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)

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N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

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log \frac{K_{P}}{K_{C}} + log R T = 0

log \frac{K_{p}}{K_{c}} + log R T = 0

K_{p}

K_{c}

2 H I_{(g)} ⟶ H_{2 (g)} + I_{2 (g)}

2 N H_{3 (g)} ⟶ N_{2 (g)} + 3 H_{2 (g)}

2 N O_{(g)} ⟶ N_{2 (g)} + O_{2 (g)}

P C l_{5 (g)} ⟶ P C l_{3 (g)} + C l_{2 (g)}

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

2 H I (g) ⇌ H_{2} (g) + I_{2} (g)

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

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