Question

Lowest unoccupied molecular orbital of $C_2$ molecule is

• A. $\sigma 2p_z$
• B. $\pi 2p_x$
• C. ${\sigma }^{\ast }2p_z$
• D. ${\pi }^{\ast }2p_x$

Answer 1

The correct option is A $\sigma 2p_z$

Answer (2)
$C_2\left(12\right):\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\{\begin{array}{cc}\pi 2p_x^2& \\ & \sigma 2p_z\\ \pi 2p_y^2& \end{array}$
LUMO is $\sigma 2p_z$