Lowest value of variance can be:

1

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- 1

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0

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None of these

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Solution

The correct option is A $0$
We know that $V a r (x) = E (X^{2}) - (E (x))^{2}$

Variance is non-negative because the squares are positive or zero.

Therefore, $V a r (X) \geq 0$

Hence, the lowest value of variance is $z e r o$

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