Question

LVDT and bourdon tube combination is used to measure pressure. The voltage output of LVDT is given by $V_o=K{P}_{in}$ where K = constant of proportionality and $P_{in}$ is input pressure. If input pressure is 10 kPa and K = ${10}^{-4}$V/Pa then in this arrangement:

• A. Voltage output of LVDT is 1V and LVDT is a primary transducer.
• B. Voltage output of LVDT is 0.1V and LVDT is a primary transducer.
• C. Voltage output of LVDT is 1V and LVDT is a secondary transducer.
• D. Voltage output of LVDT is 0.1V and LVDT is a secondary transducer.

Answer 1

The correct option is C Voltage output of LVDT is 1V and LVDT is a secondary transducer.

Given $V_0=K{P}_{in}$
$K={10}^{-4}V/P_a$
$P_{in}={10}^4{P}_a$
$\therefore V_o=1V$
And LVDT is a secondary transducer