Question

$m^3$ $\ge$ $m^2$ . To satisfy this condition, $m$ can be

• A. a positive integer
• B. any number between 0 and 1
• C. a negative integer
• D. 4

Answer 1

Answer: (A), (D)

4

The cube of a positive number is positive but the cube of a negative number is negative.
e.g: $2^3>2^2\text{and}(-2{)}^3<(-2{)}^2$

The cube of any number between 0 and 1 is less than its square. Any number greater than 1 will have its cube greater than its square.
e.g ${0.2}^3<{0.2}^2$
$\text{as}{0.2}^3=0.008{0.2}^2=0.04$