Question

$M$ is the molecular mass of $KMn{O}_4$. What will be its equivalent weight when it is converted into $K_{2}Mn{O}_4$?

• A. $M$
• B. $M/3$
• C. $M/5$
• D. $M/7$

Answer 1

The correct option is A $M$

Equivalent Mass$=\frac{MolecularMass}{n-factor}$

Here; $n-$factor$=$ (change in $O.N$ of any element )

The oxidation state of $Mn$ in $KMn{O}_4$ is +7 and in $K_{2}Mn{O}_4$ is +6.

$\therefore n$-factor $=1$

$\therefore$ Equivalent mass$=\frac{M}{1}=M$.