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Standard XII
Chemistry
Resonance
Maam bonding ...
Question
Maam bonding pair electron include both bp and lp??
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Similar questions
Q.
Choose the correct order of repulsions between bond pairs and lone pairs of electrons.
LP: lone pair of electrons
BP: bond pair of electrons
Q.
Give the correct order of initials
T
or
F
for the following statements. Use
T
if statement is true and use
F
if the statement is false:
(I) The order of repulsion between pair of electrons is
l
p
−
l
p
>
l
p
−
b
p
>
b
p
−
b
p
where
l
p
=
lone pair
,
b
p
=
bond papir
(II) In general, as the number of lone pair of electrons on central atom increases , value of bond angle from normal bond angle also increases.
(III) The number of lone pair on
O
in
H
2
O
is
2
while on
N
in
N
H
3
is 1.
(IV) The structures of xenon flourides and xenon oxyflourides could not be explained on the basis of VSEPR theory.
Q.
Assertion :The experimentally determined
N
−
F
bond length in
N
F
3
is greater than the sum of the single bond covalent bond radii of
N
and
F
. Reason:
N
and
F
both have high electron density due to smaller atomic radii. Thus,
l
p
−
b
p
repulsion increases bond-length.
Q.
Assertion :
N
-atom in
N
H
3
is
s
p
3
hybridised and bond angle is
107
o
. Reason:
l
p
−
b
p
repulsion (VSEPR) decreases bond angle to
107
o
.
Q.
Hybridization is the chemist's attempt to explain the observed molecular shape by constructing hybridized atomic orbitals with the appropriate inter orbital angles. The molecule for which deviation from a normal bond angle is observed,
V
S
E
P
R
theory suggests electron pair repulsive interaction (
l
p
−
l
p
>
l
p
−
b
p
>
b
p
). While from hybridization point of view that is a departure from normal hybridization because the angle between any equivalent hybrid orbitals determines the fraction of s and p characters of the hybrid and vice-versa.
In which species number of lone pairs on iodine and number of d-orbitals used in hybridization by iodine are the same?
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