Magnetic moment od iron in -FeH2O6-2- is -24 BM-If true enter 1- else enter 0-

The correct option is A 1The metal is Fe. Complex is therefore nbsp; Fe( H _ 2 O) ^ 3+ _ 6 , Fe(III) d6 high spin. Should have one dd transition in nbsp ...

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Standard XII

Chemistry

Valence Bond Theory

Magnetic mome...

Question

Magnetic moment od iron in $[F e (H_{2} O)_{6}]^{2 +}$ is $\sqrt{24} B M$ .
If true enter 1, else enter 0.
1

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Solution

The correct option is A 1
The metal is Fe. Complex is therefore ${F e (H_{2} O)}^{3 +}_{6}$ , Fe(III) d6 high spin. Should have one dd transition in visible, and because it is a 5 T2g ground state the magnetic moment should deviate from the spin only value (which would give S =2.0). Adding one electron to compound gives B which is ${F e (H_{2} O)}^{2 +}_{6}$ , Fe(III) d7 high spin. Three dd transitions are predicted, and the 4 T2g ground state again should lead to magnetic moments that deviate from the spin only value (for which S = 1.5).-- The magnetic moment comes out to be $\sqrt{24} B M$

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Magnetic moment od iron in [Fe(H2O)6]2+ is √24BM.If true enter 1, else enter 0.1

Magnetic moment od iron in $[F e (H_{2} O)_{6}]^{2 +}$ is $\sqrt{24} B M$ .
If true enter 1, else enter 0.
1