Question

Magnetic moment of $V^{2+}$ = Magnetic moment of $C{o}^{2+}$ if true enter 1, if false enter 0.

Answer 1

The correct answer is 1.

Magnetic moment of $V^{2+}=$ Magnetic moment of $C{o}^{2+}=$ 3.87 B.M

Both elements have 3 unpaired electrons.

$\mu =\sqrt{\left(n\right(n+2)}$

$\mu =\sqrt{\left(3\right(3+2)}$

$\mu =3.87$ B.M.
Note: The electronic configuration of $V^{2+}$ is $\left[Ar\right]3d^3$
The electronic configuration of $C{o}^{2+}$ is $\left[Ar\right]3d^7$