The correct option is
C 1.6JDue to weight of block m, let spring gets elongated by distance x.As one end of the rope is fixed , the block of mass m will go down by distance 2x.
Given:
Initial Velocity u=0 and at maximum extension
spring will come to rest for a moment so final Velocity v=0.
change in kinetic energy ΔKE=12mv2−12mu2
ΔKE=0
From work energy theorem , it is known
ΔKE=Wg+Wf+Ws, where Wg is work done by gravity,
Wf is work done by friction on block of mass 2m and Ws is work done by spring.
Wg=mg×2x=1×10×2x=20x
Ws=−12kx2=−0.5×100x2=−50x2
Wf=−μ2mgx=−0.8×2×10x=−16x
putting values in
ΔKE=Wg+Wf+Ws
0=20x−50x2−16x
x=0.08m
x=80cm
work done by gravity
Wg=mg×2x=1×10×2×0.08=1.6J