Mahendra and Virat are sitting at a distance of $1$ metre from each other. Their masses are $75 k g$ and $80 k g$ respectively. What is the gravitational force between them?

Open in App

Solution

Given : $r = 1$ $m$ , $m_{1} = 75 k g$ , $m_{2} = 80 k g$ and $G = 6.67 \times 10^{- 11} N m^{2} / {k g}^{2}$
According to Newton’s law of gravitation:
$F = \frac{G m_{1} m_{2}}{r^{2}}$
$= \frac{6.67 \times 10^{- 11} \times 75 \times 80}{1^{2}} N$
$= 4.002 \times 10^{- 7} N$
The gravitational force between Mahendra and Virat is $4.002 \times 10^{- 7}$ $N$ .

Suggest Corrections

Similar questions

Calculate the force of gravitation between two object of masses 80 kg and 120 kg kept at a distance of 10 m of each other.

Two point objects with different masses are kept at a distance $R$ apart from each other. If the gravitational force between them is $F$ , then:

Two particles are placed at some distance from each other. If, keeping the distance between them unchanged, the mass of each of the two particles is doubled, the value of gravitational force between them will become :
(a) $\frac{1}{4}$ times
(b) $\frac{1}{2}$ times
(c) 4 times
(d) 2 times