Two bodies of masses m1 and m2 are placed at distance X from each other. If X is kept constant and the masses of the two bodies are increased to 2m1, and 2m2, then the value of gravitational force between them will become
Two bodies of masses m1 and m2 are placed at distance X from each other. If X is kept constant and the masses of the two bodies are increased to 2m1, and 2m2, then the value of gravitational force between them will become
The correct option is B 4 times
Answer is C.
The force of
gravitational attraction is directly dependent upon the masses of both objects
and inversely proportional to the square of the distance that separates their
centres. Newton's conclusion about the magnitude of gravitational forces is
summarised symbolically as
F∝m1.m2X2
F=Gm1.m2X2 Where, G: Gravitational constant
where, m1 and m2 are
masses of the object and X is the distance of sepration between them.
In this case, X is kept
constant and the masses of the two bodies are increased to 2m1 and 2m2. So, the
gravitational force will become F′=2m1.2m2X2,thatis,F′=4m1.m2X2.
that is F′=4F
Hence, the magnitude of the gravitational force between them will increase be 4 times.
Answer is C.
The force of gravitational attraction is directly dependent upon the masses of both objects and inversely proportional to the square of the distance that separates their centres. Newton's conclusion about the magnitude of gravitational forces is summarised symbolically as
F∝m1.m2X2
F=Gm1.m2X2 Where, G: Gravitational constant
where, m1 and m2 are masses of the object and X is the distance of sepration between them.
In this case, X is kept constant and the masses of the two bodies are increased to 2m1 and 2m2. So, the gravitational force will become F′=2m1.2m2X2,thatis,F′=4m1.m2X2.
that is F′=4F
Hence, the magnitude of the gravitational force between them will increase be 4 times.
