wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Male gametes in diploid maize plants have 10 chromosomes in their nucleus. What would be the number of chromosomes in its female gamete, zygote and the cells of the seedling respectively?

A
20, 10, 10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10, 20, 20
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
10, 10, 10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10, 10, 20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 10, 20, 20
Chromosome number in male gamete = 10.

Therefore the number of chromosome in female gamete will also be 10.
Since the plant is diploid, zygote will be 2n (n = number of chromosomes in the haploid set) as it is formed from the fusion of two haploid gametes.
2n = 2x10 = 20
Seedlings are the product of division and differentiation of zygote so it will also be diploid which, here is 20.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Events in Sexual Reproduction
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon