Man lifts a luggage of $12 k g$ from the ground and puts it on his head $1.9 m$ above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity $= 10 m s^{- 2}$ .

200 J

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220 J

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228 J

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240 J

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Solution

The correct option is C $228 J$
Given:
Mass $m = 12 k g$ ,
Acceleration due to gravity $g = 10 m s^{- 2}$ ,
Displacement $S = 1.9 m$ .
Force $F$ is calculated as
$F = m \times g = 12 \times 10 = 120 N$
Work done by the man on luggage $= F o r c e \times d i s p l a c e m e n t$
$= 120 \times 1.9 = 228 J$
Hence, the required work done is $228 J$ .

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Man lifts a luggage of 12kg from the ground and puts it on his head 1.9m above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity=10ms−2.

The correct option is C 228JGiven: Mass m=12kg, Acceleration due to gravityg=10 ms−2, Displacement S=1.9 m. Force F is calculated as F=m×g=12×10=120N Work done by the man on luggage=Force×displacement =120×1.9=228J Hence, the required work done is 228J.

Man lifts a luggage of $12 k g$ from the ground and puts it on his head $1.9 m$ above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity $= 10 m s^{- 2}$ .