Question

Manganese$\left(IV\right)$oxide, lead$\left(IV\right)$oxide, and red lead$\left({\mathrm{Pb}}_3{\mathrm{O}}_4\right)$ react with concentrated hydrochloric acid liberating chlorine.
Write the equation for the reaction of concentrated hydrochloric acid with $\left({\mathrm{Pb}}_3{\mathrm{O}}_4\right)$

Answer 1

• Red lead which is also known as lead tetraoxide reacts with hydrochloric acid to form lead chloride and greenish-yellow chlorine gas will be liberated.
• $\underset{\mathrm{red}\mathrm{lead}}{{\mathrm{Pb}}_3{\mathrm{O}}_{4_{\left(\mathrm{s}\right)}}}+\underset{\mathrm{Hydrochloric}\mathrm{acid}}{8{\mathrm{HCl}}_{\left(\mathrm{aq}\right)}}\to \underset{\mathrm{Lead}\mathrm{chloride}}{3{{\mathrm{PbCl}}_2}_{\left(\mathrm{aq}\right)}}+4{\mathrm{H}}_2{\mathrm{O}}_{\left(\mathrm{l}\right)}+\underset{\mathrm{Greenish}-\mathrm{Yellow}}{{\mathrm{Cl}}_{2_{\left(\mathrm{g}\right)}}}$