Question

Manju starts for her school at 8:16 a.m. on her
bicycle. If she travels at a speed of 12 km/h, then
she reaches her school late by 7 minutes but on
travelling at 18 km/h, she reaches the school
10 minutes early. At what time does the school
start?

Answer 1

Dear Student

Let x be the time taken for the student to reach the school on time

speed= $\frac{dis\tan ce}{time}$
distance = speed * time
speed = 12km/h

distance =12 ∗(x+7)
distance =12 x+84

Second case

distance=speed∗time
speed = 18km/h

distance=18∗(x−10)

distance=18x−180
Now equate both the expressions as they are describing the same distance

18x - 180 =12x + 84
6x = 264
x = 44 minutes
school starts at 9: am

Regards
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