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Question

Manu needs ₹7.50 to buy an eraser. He already has a few ₹2 coins and a few 50 paise coins with him. How many ₹2 coins and 50 paise coins will Manu need to buy the eraser such that he uses the least number of 50 paise coins?


A

Three ₹2 coins and two 50 paise coins

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B

Two ₹2 coins and four 50 paise coins

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C

Three ₹2 coins and three 50 paise coins

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D

Three ₹2 coins and ten 50 paise coins

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Solution

The correct option is C

Three ₹2 coins and three 50 paise coins


As per the question,

Manu has to use least 50 paise coins. So he needs to use maximum ₹2 coins to buy the eraser.

The cost of the eraser = ₹7.50

The value of two ₹2 coins
= ₹2×2 = ₹4

The value of three ₹2 coins
= ₹2×3 = ₹6

The value of four ₹2 coins
= ₹2×4
= ₹8

So, Manu can use three ₹2 coins.

The remaining money
= ₹7.50 - 6
= ₹1.50

We know that, ₹1 = 100 paise

₹1.50 = ​​​​​​​₹1.50 × 100 = 150 paise

The value of three 50 paise coins
= 50×3
= 150 paise

Hence, Manu will need three ₹2 coins and three 50 paise coins to buy the eraser.


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