Mariam bought two fans for Rs 3605. She sold one at a profit of 15% and the other at a loss of 9%. If Mariam obtained the same amount for each fan, find the cost price of each fan.

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Solution

$It is given that t h e S . P is same for both the fans . Let C . P of t h e first fa n b e Rs . x T h e r e f o r e, C . P of t h e second fan = Rs . (3605 - x) Profit o n the first fan = 15 % Loss o n the second fan = 9 % For the first fan, S . P = C . P (\frac{100 + gain %}{100}) = x (\frac{115}{100}) = \frac{23 x}{20} For the second fan, S . P = C . P (\frac{100 - loss %}{100}) = (3605 - x) (\frac{91}{100}) Since S . P o f b o t h t h e f a n s i s t h e same, \frac{23 x}{20} = (3605 - x) (\frac{91}{100}) 2300 x = 91 (72100 - 20 x) 2300 x = 6561100 - 1820 x 4120 x = 6561100 x = Rs . 1592.50 Thus, C . P of t h e first fan i s Rs . 1592.50 . C . P of t h e second fan = Rs . (3605 - 1592.50) = Rs . 2012.50$

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sir I have no any doubt in answer I have only one doubt that why we assume sp to 100 .

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