Mark out the correct order of dipole moment for the following compounds:

I > I I > I I I

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I I > I I I > I

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I I I > I I > I

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I I I > I > I I

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Solution

The correct option is C $I I I > I I > I$
The carboxyl group of propanone is the most polar due to sigma ' $σ$ ' bonds in the adjacent $C - H$ bond. As the no. of carbon atoms in a molecule decreases polarity also decreases & polarity is directly proportional to the dipole moment.

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Mark out the correct order of dipole moment for the following compounds:

The correct option is C III>II>IThe carboxyl group of propanone is the most polar due to sigma 'σ' bonds in the adjacent C−H bond. As the no. of carbon atoms in a molecule decreases polarity also decreases & polarity is directly proportional to the dipole moment.

The correct option is C $I I I > I I > I$
The carboxyl group of propanone is the most polar due to sigma ' $σ$ ' bonds in the adjacent $C - H$ bond. As the no. of carbon atoms in a molecule decreases polarity also decreases & polarity is directly proportional to the dipole moment.