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Question

Mark the correct alternative in each of the following :

In any ΔABC, 2(bc cos A+ca cos B+ab cos C)=


A

abc

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B

a+b+c

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C

a2+b2+c2

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D

1a2+1b2+1c2

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Solution

The correct option is C

a2+b2+c2


2bc cos A+2ca cos B+2ab cos C ...(i)Putting the values of cos A, cos B and cos C in (i), we get=2bc(b2+c2a22bc)+2ca(c2+a2b22ca)+2ab(a2+b2c22ab)=(b2+c2a2)+(c2+a2b2)+(a2+b2c2)=a2+b2+c2


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