Three biased coins are tossed 800 times.
∴ Total number of trials = 800
Let E be the event of occurrence of two heads and F be the event of occurrence of all heads.
∴ Probability of occurrence of two heads = P(E) = .....(1)
Now,
Number of trials of occurrence of all heads (or three heads)
= Total number of trials − Number of trials of occurrence of no head − Number of trials of occurrence of one head − Number of trials of occurrence of two heads
= 800 − 120 − 280 − x
= 400 − x
∴ Probability of occurrence of all heads = P(F) = .....(2)
It is given that,
Probability of occurrence of two heads = 3 × Probability of occurrence of all heads
[From (1) and (2)]
Thus, the value of x is 300.
Hence, the correct answer is option (c).