Question

Mark the correct alternative in each of the following:

Two different coins are tossed simultaneously. The probability of getting at least one head is

(a) $\frac{1}{4}$ (b) $\frac{1}{8}$ (c) $\frac{3}{4}$ (d) $\frac{7}{8}$ [CBSE 2014]

Answer 1

When two coins are tossed simultaneously, all possible outcomes are HH, HT, TH, TT.

∴ Total number of outcomes = 4

The favourable outcomes are HH, HT, TH.

So, the favourable number of outcomes are 3.

∴ P(getting at least one head) = $\frac{\mathrm{Favourable}\mathrm{number}\mathrm{of}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{outcomes}}=\frac{3}{4}$

Hence, the correct answer is option C.