Question

Two coins are tossed simultaneously. the probability of getting at least one head is ___________.

• A. $\frac{1}{4}$
• B. $\frac{1}{2}$
• C. $\frac{3}{4}$
• D. $0$

Answer 1

The correct option is C $\frac{3}{4}$

at least one head is required,

the probability of getting exactly one head $=\frac{1}{2}\times \frac{1}{2}+\frac{1}{2}\times \frac{1}{2}$

$=\frac{2}{4}$

the probability of getting both heads is $\frac{1}{2}\times \frac{1}{2}=\frac{1}{4}$

Total required probability is $\frac{2}{4}+\frac{1}{4}=\frac{3}{4}$