Question

Two coins are tossed simultaneously. The probability of getting at least 1 head is

• A. $\frac{2}{3}$
  
• B. $\frac{1}{2}$
  
• C. $\frac{3}{4}$
  
• D. $\frac{1}{4}$
  

Answer 1

The correct option is C $\frac{3}{4}$


Total number of outcomes when two coins are tossed = 4 (HH, HT, TH, TT)
Outcomes having at least 1 head: HH, HT, TH
$\therefore \text{Number of favourable outcomes}=3$
$\therefore \text{P(At least one head)}=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$
$=\frac{3}{4}$
Hence, the correct answer is option (c).