Question

Mass of carbon present in $512g$ of $C_{12}{H}_{22}{O}_{11}$ is

• A. $216g$
• B. $144g$
• C. $297$
• D. $237$

Answer 1

The correct option is A $216g$

Molar mass of $C_{12}{H}_{22}{O}_{11}=342.3g/mol$

Molar mass of $C_{12}=12.01g/mol\times 12=144.12g/mol$

Carbon percentage in sucrose's total mass$=\frac{144.12}{342.3}\times 100=42.1\%$

Mass of $C_{12}{H}_{22}{O}_{11}=512g$

Mass of $C_{12}=0.421\times 512g=216g$

Mass of carbon present in $512g$ of $C_{12}{H}_{22}{O}_{11}$ is $216g$