Mass of $H_{2} O$ in 1000 kg $C u {S O}_{4}$ . $5 H_{2} O$ is:

360.5 kg

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36.05 kg

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3605 kg

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3.605 kg

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Solution

The correct option is B 360.5 kg
Moles of $C u S O_{4} \cdot 5 H_{2} O = \frac{1000}{249.5} = 4.008$ $K . m o l e s$

No. of moles of $H_{2} O = 5 \times 4.008 = 20.04$ $K . m o l e s$

Mass of $H_{2} O = 20.04 \times 18 = 360.5$ $k g$

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Similar questions

Q. If

{C u S O}_{4} \cdot 5 H_{2} O (s) ⇌ {C u S O}_{4} \cdot {3 H}_{2} O (s) + {2 H}_{2} O (l) K_{p} = 1.086 \times 10^{- 4} {a t m}^{2} a t 25^{o} C

The efflorescent nature of

{C u S O}_{4} \cdot {5 H}_{2} O

can be noticed when vapour pressure of

H_{2} O

in atmosphere is:

Which of the following are the products formed on heating $C u S O_{4} . 5 H_{2} O (s)$ ?

$C u S O_{4} .5 H_{2} O$ is blue in colour while $C u S O_{4}$ is colourless. Why?

If $C u S O_{4 (s)}$ . $5 H_{2} O_{(s)}$ $⇋$ $C u S o_{4}$ . $H_{2} O_{(s)}$ + $2 H_{2} O$ (g) $K_{p}$ = 1.0 x $10^{- 4}$ atm2 at $250^{\circ}$ . The efflorescent nature of CuSO4 . 5H2O can be noticed when vapour pressure of H2O in atmosphere is:

C u {S O}_{4} \cdot 5 H_{2} O

is blue in colour whereas anhydrous

C u {S O}_{4}

is colourless. Why?

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Mass of H2O in 1000 kg CuSO4. 5H2O is:

The correct option is B 360.5 kgMoles of CuSO4⋅5H2O=1000249.5=4.008 K.moles No. of moles of H2O=5×4.008=20.04 K.molesMass of H2O=20.04×18=360.5 kg

Mass of $H_{2} O$ in 1000 kg $C u {S O}_{4}$ . $5 H_{2} O$ is:

The correct option is B 360.5 kg
Moles of $C u S O_{4} \cdot 5 H_{2} O = \frac{1000}{249.5} = 4.008$ $K . m o l e s$

No. of moles of $H_{2} O = 5 \times 4.008 = 20.04$ $K . m o l e s$

Mass of $H_{2} O = 20.04 \times 18 = 360.5$ $k g$