Question

Mass of thin long metal rod is 2 kg and its moment of inertia about an axis perpendicular to the length of rod and passing through its one end is $0.5kg{m}^2$. Its radius of gyration is:

• A. $20cm$
• B. $40cm$
• C. $50cm$
• D. $1m$

Answer 1

The correct option is C $50cm$

$I=0.5kg{m}^2$
m= 2kg
K= radius of gyration

$2k^2=0.5$

$k^2=\sqrt{0\cdot 25}$

$\therefore k=\sqrt{0.25}m=50cm$