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Question

Mass of upper block and lower block kept over the table is 2 kg and 1 kg respectively and coefficient of friction between the blocks is 0.1. Table surface is smooth. The maximum mass m for which all the three blocks move with same acceleration is (g=10 m/s2)


A
1 kg
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B
2/3 kg
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C
1/3 kg
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D
3/4 kg
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Solution

The correct option is D 3/4 kg
Drawing FBDs and writing force equations,

Tfr=2a
f12=μ×2g=0.1×2×10=2 N
T2=2a(1)

f12=1.a=2(2)
a=2 m/s2
T=3a=3×2=6 N

mgT=ma
mg6=m×2
10 m2 m=6
8 m=6
m=6/8=3/4 kg

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