Question

Match column I with column II.

Answer 1

$sin\theta =\frac{-\sqrt{3}}{2},\theta =-\frac{\pi }{3}$
$cos\theta =\frac{-1}{2},\theta =2\frac{\pi }{3}$
$tan\theta =\sqrt{3},\theta =\frac{\pi }{3}$
$cot2\theta =-\sqrt{3},2\theta =5\frac{\pi }{6}\Rightarrow \theta =\frac{5\pi }{12}$