Question

Match column -I with column-II and select the correct answer using the codes given below :
Column-I Column -II
(A) $1$ horsepower (p) $10$ m fall of a unit mass
(B) $3.6\times {10}^6$ joule (q) Work is zero
(C) $100$ joule (r) $746$ watt
(D) Zero displacement (s) Commercial unit of energy

• A. $\left(A\right)\to q,\left(B\right)\to r,\left(C\right)\to p,\left(D\right)\to s$
• B. $\left(A\right)\to p,\left(B\right)\to q,\left(C\right)\to s,\left(D\right)\to r$
• C. $\left(A\right)\to s,\left(B\right)\to q,\left(C\right)\to r,\left(D\right)\to p$
• D. $\left(A\right)\to r,\left(B\right)\to s,\left(C\right)\to p,\left(D\right)\to q$

Answer 1

The correct option is D $\left(A\right)\to r,\left(B\right)\to s,\left(C\right)\to p,\left(D\right)\to q$

When displacement is zero work is zero.
As $work=force\times displacement$

Energy in case of $10m$ fall of a unit mass
$m=1kg$; $h=10m$;$g=$$10m{s}^{-2}$
$\therefore E=mgh=1\times 10\times 10joule=100joule$

$1hp=746watt$

Commercial unit of energy is $=3.6\times {10}^{6}J$