Question

Match Column I with Column II.

	Column I		Column II
A	Dumas method	$\left(i\right)$	$AgN{O}_3$
B	Kjeldahl’s method	$\left(ii\right)$	Silica gel
C	Carius Method	$\left(iii\right)$	Nitrogen gas
D	Chromatography	$\left(iv\right)$	Free radicals
E	Hormolysis	$\left(v\right)$	Ammonium Sulphate

Answer 1

(A) Dumas method

Dumas method is used for the estimation of the nitrogen gas. In this method nitrogen containing organic compounds, when heated with copper oxide in an atmosphere of carbon dioxide, yields free nitrogen in addition to carbon dioxide and water.

Hence, the correct match is :

$\left(A\right)\to \left(iii\right)$

(B) Kjeldahl’s method

In this method, nitrogen-containing compound is treated with concentrated $H_{2}S{O}_4$ to get ammonium sulphate which liberates ammonia on treating with $NaOH$; The liberated ammonia gas is absorbed in an excess of standard solution of sulphuric acid. So, the amount of ammonia produced is determined by estimating the amount of sulphuric acid consumed in the reaction.

Organic compound $+H_{2}S{O}_4\to (N{H}_4{)}_{2}S{O}_4$

Since, this method involves formation of ammonium sulphate during the process.
Hence, the correct match is :

$\left(B\right)\to \left(v\right)$

(C) Carius method

The Carius method can be used for the estimation of halogen. In this method a known mass of an organic compound is heated with fuming nitric acid in the presence of silver nitrate $\left(AgN{O}_3\right)$. The halogen present forms the corresponding silver halide $\left(AgX\right)$. Then, It is filtered, washed, dried and weighed.

So, this method involves silver nitrate as one of the reagent.
Hence, the correct match is :

$\left(C\right)\to \left(i\right)$

(D) Chromatography

Adsorption chromatography is used to separate mixtures into their components. It is based on the fact that different compounds are adsorbed on an adsorbent to different degrees.

Commonly used adsorbents are silica gel and alumina.

Hence, the correct match is :

$\left(D\right)\to \left(ii\right)$

(E) Homolysis

Homolysis of covalent compound form free radicals

Hence, the correct match is :

$\left(E\right)\to \left(iv\right)$

So, the correct matches can be represented as:

$\left(A\right)\to \left(iii\right)$ , $\left(B\right)\to \left(v\right)$ , $\left(C\right)\to \left(i\right)$ , $\left(D\right)\to \left(ii\right)$ , $\left(E\right)\to \left(iv\right)$ .