CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
281
You visited us 281 times! Enjoying our articles? Unlock Full Access!
Question

Match List I and List II

List-I List-II

a) P-V graph(T is constant) e) St. line cutting temp axis at - 2730

b) P-T graph(V is constant) f) Rectangular hyperbola

c) V-T graph(pressure P is constant) g) A st.line parallel to axis

d) PV- P garph h) St. line passing trhough origin (T is constant)



A
a-g,b-e,c-h, d-f.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a-h, b-f c-g, d-e.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a-e, b-g,c-f, d-h.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a-f, b-h, c-e,d-g.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D a-f, b-h, c-e,d-g.
(a) P-V graph (T is constant):
PV=nRT
at constant temperature
PV=constant
Pα1V
so it will be
Rectangular hyperbola.
(b) P-T Graph
(V is constant) :
PV=nRT
at constant volume
PαT
pressure is proportional to T, so it will be straight line passing through origin.
c) V-T graph(P is constant) :
PV=nRT
at constant pressure
VαT
volume is proportional to T(Kelvin),so it will be straight line passing through origin, but if temperature is taken in oC, then it will cut temperature axis at 273oC
(d) PV - P Graph (T is constant) :
PV=nRT
at constant Temperature
PV=constant
PV is constant for constant temperature,so it will be straight line parallel to P axis.
235999_25722_ans.gif

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Equation of State
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon