Question

Match List-I (Compounds) with List-II (Oxidation states of nitrogen) and select answer using the codes given below the lists.

	List -I		List-II
$\left(a\right)$	$Na{N}_3$	$\left(1\right)$	$+5$
$\left(b\right)$	$N_2{H}_2$	$\left(2\right)$	$+2$
$\left(c\right)$	$NO$	$\left(3\right)$	$-\frac{1}{3}$
$\left(d\right)$	$N_2{O}_5$	$\left(4\right)$	$-1$

• A. a$\to$1, b$\to$4, c$\to$2, d$\to$1
• B. a$\to$4, b$\to$3, c$\to$2, d$\to$1
• C. a$\to$3, b$\to$4, c$\to$1, d$\to$2
• D. a$\to$3, b$\to$4, c$\to$2, d$\to$1

Answer 1

The correct option is D a$\to$3, b$\to$4, c$\to$2, d$\to$1

Let oxidation state of $N$ be $x$.

In $Na{N}_3$,
$+1+3x=03x=-1x=-\frac{1}{3}$

In $N_2{H}_2$,
$2x+2(+1)=02x=-2x=-1$

In $NO$,
$x-2=0x=+2$

In $N_2{O}_5$,
$2x-10=02x=+10x=+5$