Match List-I Monomer with List-II Polymer and select the correct answer using the codes given below the lists- - List-I List-II- IHexamethylenediamine A-Bakelite- IIPhenol B- Dacron- IIIPhthalic acid C- Glyptal- IVTerephthalic acid D- Melamine- E- Nylon-6-6- -

Monomers for Nylon 6,6 are hexamethylene diamine and adipic acid. nbsp;Bakelite is obtained by polymerisation of phenol and formaldehyde. Glyptal is the cond ...

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Byju's Answer

Standard XI

Chemistry

Condensation Polymerization

Match List-I ...

Question

Match $L i s t - I$ (Monomer) with $L i s t - I I$ (Polymer) and select the correct answer using the codes given below the lists:
$\begin{matrix} List-I & List-II (I) Hexamethylenediamine & A.Bakelite (I I) Phenol & B. Dacron (I I I) Phthalic acid & C. Glyptal (I V) Terephthalic acid & D. Melamine E. Nylon-6,6 \end{matrix}$

I - E, I I - A, I I I - B, I V - C

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I - E, I I - A, I I I - C, I V - B

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I - D, I I - C, I I I - A, I V - B

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I - D, I I - C, I I I - A, I V - B

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Solution

The correct option is B $I - E, I I - A, I I I - C, I V - B$
Monomers for $N y l o n 6, 6$ are hexamethylene diamine and adipic acid. Bakelite is obtained by polymerisation of phenol and formaldehyde. Glyptal is the condensation polymer of ethylene glycol and phthalic acid. The monomers of Dacron are terepthalic acid and ethylene glycol.
Hence, the correct combination is
$Hexamethylenediamine \to Nylon-6,6$
$Phenol \to Bakelite$
$Phthalic acid \to Glyptal$
$Terepthalic acid \to Dacron$

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Match List−I (Monomer) with List−II (Polymer) and select the correct answer using the codes given below the lists: List-IList-II(I)HexamethylenediamineA.Bakelite(II)PhenolB. Dacron(III)Phthalic acidC. Glyptal(IV)Terephthalic acidD. MelamineE. Nylon-6,6