Question

Match list I with list II and select the correct answer by using codes given below:

	List I	List II
A	$C{F}_{3}CHC{l}_2$	1. $E_1$
B		2. $E_2$
C	$C{H}_{3}C{H}_{2}C{H}_{2}Br$	3. $E_{1}cB$

• A. (A)-3, (B)-1, (C)-2
• B. (A)-1, (B)-2, (C)-3
• C. (A)-3, (B)-2, (C)-1
• D. (A)-2, (B)-1, (C)-3

Answer 1

The correct option is A (A)-3, (B)-1, (C)-2

All the primary alkyl halides give $E_2$-mechanism easily
So, $C{H}_{3}C{H}_{2}C{H}_{2}Br$ will show $E_2$-mechanism
Tertiary alcohols give $E_1$-mechanism because carbocation so formed is the most stable.
So, B will show $E_1$-mechanism.
Strong EWG at the $\beta$ carbon and poor leaving group favors the E1cb reaction.
$C{F}_{3}CHC{l}_2$ has Fluorine at the $\beta$ carbon thus it will shows $E_{1}cB$ mechanism.