Question

Match List-I with List-II and choose the correct answer. from the codes given below.
$\begin{array}{cc}\text{List - I}& \text{List - II}\\ \text{P. Limestone is heated}& \text{(i) Electrolysis}\\ \text{Q. Magnesium wire is burnt in air}& \text{(ii) Decomposition reaction}\\ \text{R. White ppt. of silver chloride is}& \text{(iii) Combination reaction}\\ \text{formed when silver nitrate is added}& \\ \text{to sodium chloride solution}& \\ \text{S. Electricity is passed through}& \text{(iv) Double displacement}\\ \text{acidulated water}& \text{reaction}\end{array}$

• A. $\text{P-(iv), Q-(ii), R-(i), S-(iii)}$
• B. $\text{P-(ii), Q-(iii), R-(iv), S-(i)}$
• C. $\text{P-(ii), Q-(iv), R-(iii), S-(i)}$
• D. $\text{P-(i), Q-(ii), R-(iv), S-(iii)}$

Answer 1

The correct option is B $\text{P-(ii), Q-(iii), R-(iv), S-(i)}$

(P). Heating of limestone is a decomposition reaction.
$CaC{O}_3\left(s\right)\stackrel{\Delta }{\to }CaO\left(s\right)+C{O}_2\left(g\right)$

(Q). Burning of magnesium wire in air is type of combination reaction.
$Mg\left(s\right)+O_2\left(g\right)\to MgO\left(s\right)$

(R). Double displacement reaction:
$AgN{O}_3\left(aq\right)+NaCl\left(aq\right)\to \underset{\text{(white ppt)}}{AgCl\left(s\right)}+NaN{O}_3\left(aq\right)$

(S). Electrolysis of water containg acid produces oxygen gas at the anode.