Question

Match List-I with List-II.

List-I	List-II
$\left(a\right)$ Isothermal	$\left(i\right)$ Pressure constant
$\left(b\right)$ Isochoric	$\left(ii\right)$ Temperature constant
$\left(c\right)$ Adiabatic	$\left(iii\right)$ Volume constant
$\left(d\right)$ Isobaric	$\left(iv\right)$ Heat content is constant

Choose the correct answer from the options given below -

• A. $\left(a\right)-\left(ii\right),\left(b\right)-\left(iv\right),\left(c\right)-\left(iii\right),\left(d\right)-\left(i\right)$
• B. $\left(a\right)-\left(ii\right),\left(b\right)-\left(iii\right),\left(c\right)-\left(iv\right),\left(d\right)-\left(i\right)$
• C. $\left(a\right)-\left(i\right),\left(b\right)-\left(iii\right),\left(c\right)-\left(ii\right),\left(d\right)-\left(iv\right)$
• D. $\left(a\right)-\left(iii\right),\left(b\right)-\left(ii\right),\left(c\right)-\left(i\right),\left(d\right)-\left(iv\right)$

Answer 1

The correct option is B $\left(a\right)-\left(ii\right),\left(b\right)-\left(iii\right),\left(c\right)-\left(iv\right),\left(d\right)-\left(i\right)$

By theory :

$\left(1\right).$ Isothermal process - Temperature is constant.

$\left(2\right).$ Isochoric process - Volume is constant.

$\left(3\right).$ Adiabatic process - Heat content is constant.

$\left(4\right).$ Isobaric process - Pressure is constant.

Hence, option $\left(B\right)$ is correct.