Question

What will be the area A of the quadrilateral in each case with their diagonal $dcm$ & the sum of their heights $(h_1+h_2)cm$.

i) $d=20,(h_1+h_2)=10$

ii) $d=15,(h_1+h_2)=20$

iii) $d=20,(h_1+h_2)=25$

iv) $d=40,(h_1+h_2)=30$

• A. d= 15,$(h_1+h_2)=20$
• B. d= 20,$(h_1+h_2)=10$
• C. d= 40,$(h_1+h_2)=30$
• D. d= 20,$(h_1+h_2)=25$

Answer 1

$\text{Area of Quadrilateral}=\frac{1}{2}d(h_1+h_2)$

i) $\text{When d}=20cm,(h_1+h_2)=10cm$

$\text{Area A}=\frac{1}{2}\times 20\times 10$

$=100c{m}^2$


ii) $\text{When d}=15cm,(h_1+h_2)=20cm$

$\text{Area A}=\frac{1}{2}\times 15\times 20$

$=150c{m}^2$


iii) $\text{When d}=20cm,(h_1+h_2)=25cm$

$\text{Area A}=\frac{1}{2}\times 20\times 25$

$=250c{m}^2$

iv) $\text{When d}=40cm,(h_1+h_2)=30cm$

$\text{Area A}=\frac{1}{2}\times 40\times 30$

$=600c{m}^2$