Question

Match the column I with column II and mark the appropriate choice.

Column I	Column II
(A) 3d-transition series	(i) Z=58 to Z=71
(B) Lanthanoid series	(ii) Z=39 to Z = 48
(C) Actinoid series	(iii) Z = 21 to Z = 30
(D) 4d-transition series	(iv) Z = 90 to Z=103

• A. (A) $\to$ (i), (B) $\to$ (ii), (C) $\to$ (iii), (D) $\to$ (iv)
• B. (A) $\to$ (ii), (B) $\to$ (iii), (C) $\to$ (iv), (D) $\to$ (i)
• C. (A) $\to$ (iii), (B) $\to$ (i), (C) $\to$ (iv), (D) $\to$ (ii)
• D. (A) $\to$ (iv), (B) $\to$ (iii), (C) $\to$ (i), (D) $\to$ (ii)

Answer 1

The correct option is C (A) $\to$ (iii), (B) $\to$ (i), (C) $\to$ (iv), (D) $\to$ (ii)

Series name	Atomic numbers	Elements
$3d$ transition series	21 to 30	$Sc$ to $Zn$
$4d$ transition series	39 to 48	$Y$ to $Cd$
Lanthanoid series	58 to 71	$Ce$ to $Lu$
Actinoid series	90 to 103	$Th$ to $Lr$