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Addition of Sulphuric Acid and Water

Match the col...

Question

Match the column I with column II and mark the appropriate choice.

Column I
Column II
(A) Aniline (i) Can be made by Gabriel phthalimide reaction
(B) N-Methylaniline (ii) Undergoes electrophilic substitution reaction with $H N O_{2}$
(C) N, N-Dimethylaniline (iii) Forms yellow oily product with $H N O_{2}$
(D) Benzylamine (iv) Gives azo dye test

(A)

\to

(iv), (B)

\to

(iii), (C)

\to

(ii), (D)

\to

(i)

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(A)

\to

(ii), (B)

\to

(iv), (C)

\to

(i), (D)

\to

(iii)

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(A)

\to

(iii), (B)

\to

(i), (C)

\to

(iv), (D)

\to

(ii)

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(A)

\to

(i), (B)

\to

(ii), (C)

\to

(iii), (D)

\to

(iv)

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Solution

The correct option is A (A) $\to$ (iv), (B) $\to$ (iii), (C) $\to$ (ii), (D) $\to$ (i)
Aniline $\to$ Gives azo dye test $.$
$N$ -Methylaniline $\to$ Forms yellow oily product with $H N O_{2}$
$N, N$ -Dimethylaniline $\to$ Undergoes electrophilic substitution reaction with $H N O_{2}$
Benzylamine $\to$ Can be made by Gabriel phthalimide reaction $.$

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	Column I		Column II
(A)	Aniline	(i)	Can be made by Gabriel phthalimide reaction
(B)	N-Methylaniline	(ii)	Undergoes electrophilic substitution reaction with $H N O_{2}$
(C)	N, N-Dimethylaniline	(iii)	Forms yellow oily product with $H N O_{2}$
(D)	Benzylamine	(iv)	Gives azo dye test

The correct option is A (A)→(iv), (B)→(iii), (C)→(ii), (D)→(i)Aniline→ Gives azo dye test.N-Methylaniline→ Forms yellow oily product with HNO2N,N-Dimethylaniline→Undergoes electrophilic substitution reaction with HNO2Benzylamine→ Can be made by Gabriel phthalimide reaction .