Question

Match the column I with column II and mark the appropriate choice.

	Column I		Column II
(A)	Methanol	(i)	Conversion of phenol to $\sigma$-hydroxybenzoic acid
(B)	Kolbe's reaction	(ii)	Heated copper at $573$K
(C)	Williamson's synthesis	(iii)	Wood spirit
(D)	Conversion of $2^o$ alcohol to ketone	(iv)	Reaction of alkyl halide with sodium alkoxide

• A. (A)$\to$(iii), (B)$\to$(iv), (C)$\to$(i), (D)$\to$(ii)
• B. (A)$\to$(iii), (B)$\to$(i), (C)$\to$(iv), (D)$\to$(ii)
• C. (A)$\to$(ii), (B)$\to$(iii), (C)$\to$(i), (D)$\to$(iv)
• D. (A)$\to$(iv), (B)$\to$(i), (C)$\to$(iii), (D)$\to$(ii)

Answer 1

Answer: (B)

(A)$\to$(iii), (B)$\to$(i), (C)$\to$(iv), (D)$\to$(ii)

Methanol is also called wood spirit as it is obtained as a by-product of wood distillation. Kolbe's reaction converts Phenol to Salicylic acid (which is o-hydroxybenzoic acid). Williamson's synthesis involves the reagents: alkyl halides and sodium alkoxide (alcohol+ $NaOH$). Finally, 2° alcohols are converted to ketones by using heated Copper at 573K.
Hence, Option B is correct.