Question

Match the column I with column II and mark the appropriate choice.

Column I	Column II
(A) $K_2{SO}_4\cdot {Al}_2{\left({SO}_4\right)}_3\cdot 24H_2{O}_{\left(aq\right)}$	(i) Bronsted base
(B) Slat of weak acid and strong base	(ii) Neutral
(C) $H_2{PO}_4$	(iii) Basic
(D) Solution of pH 6.5 at high temperature	(iv) Acidic

• A. $\left(A\right)\to \left(iv\right),\left(B\right)\to \left(iii\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(ii\right)$
• B. $\left(A\right)\to \left(iv\right),\left(B\right)\to \left(ii\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(iii\right)$
• C. $\left(A\right)\to \left(iii\right),\left(B\right)\to \left(ii\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(iv\right)$
• D. $\left(A\right)\to \left(iv\right)$, $\left(B\right)\to \left(iii\right)$,$\left(C\right)\to \left(ii\right)$, $\left(D\right)\to \left(i\right)$

Answer 1

The correct option is A $\left(A\right)\to \left(iv\right),\left(B\right)\to \left(iii\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(ii\right)$

Solution:-

(A) ${K_{2}S{O}_4.{Al}_2{\left(S{O}_4\right)}_3.24H_{2}O}_{(aq.)}\to$ Due to water solubility of ${Al}^{+3}$ ion, it is acidic in nature. $\to$ (iv) Acidic

(B) Salt of weak acid and strong base $\to$ When acids and bases react, the relative strength of the conjugated acid-base pair in the salt determines the pH of its solutions. The salt, or its solution, so formed can be acidic, neutral or basic. A salt formed between a weak acid and a strong base is a basic salt. $\to$ (iii) Basic

(C) ${H_{2}P{O}_4}^{-}\to {H_{2}P{O}_4}^{-}$ is called dihydrogen phosphate ion. It is the conjugate base of Phosphoric Acid $H_{3}P{O}_4.\to$ Bronsted base

(D) Solution of pH 6.5 at high temperature $\to$ A solution with a pH from 0 to 6 is acidic, and a solution with a pH from 8 to 14 is basic. A solution can only be considered neutral if it has a pH between 6 to 8. $\to$ (i) Neutral