Question

Match the column-I with column-II.

COLUMN-I	COLUMN-II
Group	Equilibrium Constant
(A) R$=-H$	(P) $38$
(B) R$=-C{H}_3$	(Q) $23$
(C) R$=-Et$	(R) $18$
(D) R$=-\underset{C{H}_3}{\underset{|}{C}H}-C{H}_3$	(S) $1$

• A. A-S; B-R; C-P; D-Q
• B. A-R; B-S; C-Q; D-P
• C. A-P; B-Q; C-R; D-S
• D. A-S; B-R; C-Q; D-P

Answer 1

The correct option is D A-S; B-R; C-Q; D-P

$R=-H$ $R=-C{H}_3$ $R=-Et$ $R=-CH(C{H}_3{)}_2$

$K_{eq}$ $1$ $10$ $23$ $30$

The equilibrium constant for this reaction is given as (for different $R$) :-

The steric hindrance of various species follows the order $3^0>2^0>1^0>{CH}_3^{+}>H^{+}$. So, the reaction rate will be faster in that case of that species in which stable compound are formed in the reaction.