Question

Match the Column I with Column II

	Column I (Units)		Column II (Dimensional formulae)
(A)	Pa s	(p)	$\left[M^0{L}^2{T}^{-2}{K}^{-1}\right]$
(B)	N m K${}^{-1}$	(q)	$\left[ML{T}^{-3}{K}^{-1}\right]$
(C)	J kg${}^{-1}$ K${}^{-1}$	(r)	$\left[M{L}^{-1}{T}^{-1}\right]$
(D)	W m${}^{-1}$ K${}^{-1}$	(s)	$\left[M{L}^2{T}^{-2}{K}^{-1}\right]$

• A. A - q, B - p, C - r, D - s
• B. A - p, B - q, C - s, D - r
• C. A - r, B - s, C - p, D - q
• D. A - s, B - r, C - q, D - p

Answer 1

The correct option is C A - r, B - s, C - p, D - q

(A) $Pas=\left[M{L}^{-1}{T}^{-2}\right]\left[T\right]=\left[M{L}^{-1}{T}^{-1}\right]$
A - r
(B) $Nm{k}^{-1}=\frac{\left[ML{T}^{-2}\right]\left[T\right]}{\left[K\right]}=\left[M{L}^2{T}^{-2}{K}^{-1}\right]$
B - s
(C) $Jk{g}^{-1}{k}^{-1}=\frac{\left[M{L}^2{T}^{-2}\right]}{\left[M\right]\left[K\right]}=\left[M^0{L}^2{T}^{-2}{K}^{-1}\right]$
C - p
(D) $W{m}^{-1}{k}^{-1}=\frac{\left[M{L}^2{T}^{-3}\right]}{\left[L\right]\left[K\right]}=\left[ML{T}^{-3}{K}^{-1}\right]$
D - q