Question

Match the entries given in column $A$ with appropriate ones from column $B$.

Answer 1

(A) Nitrogen

Atomic no. of nitrogen is $7$.

$3$ unpaired electrons are three. Hence, it can form $3$ bonds.

(B) Xenon

Xenon is an insert gas atom. It means it has octet configuration.

(C) Ammonia

${NH}_3$ has one lone pair of electrons. Due to repulsion between lone pair and bond pair its angle becomes ${107}^0$.

(D) Sulphur hexflouride

In this sulphur forms $6$ bonds with $6$ flourine atoms and has $0$ lone pairs. Hence, its shape will be octahedral.

(E) Hydrogen Chloride

In $HCl$, covalen bond is formed but due to electronegative difference between both the atoms, it becomes polar covalent bond.

(F) Methane

In ${CH}_4$, carbon forms $4$ bonds with $4$ hydrogen atoms. Hence its bond angle will be ${109}^0{28}^1$

(G) Water molecule

In $H_{2}O$, Oxygen has $6$ valence electrons and it forms $2$ bonds with $2$ hydrogens and $2$ lone pairs will be left on oxygen atom.