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Question

Match the entries of column I with the entries of column II in the following table.

Column I | Column II |

(A) | (P) Wires 1 and 2 attract each other. |

(B) | (Q) Wires 1 and 2 do not exert any force on each other. |

(C) | (R) Magnetic fields at point P due to wires 1 and 2 are perpendicular to each other. |

(D) Wires 1 and 2 are in the same plane without touching each other. |
(S) Magnetic fields at point P due to wires 1 and 2 are in the same direction. |

Which of the following option has the correct combination, considering column I and column II?

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Solution

The correct option is **B** B→Q,R

In case (A)

Due to I1, →B at P, from right-hand thumb rule, is upward and due to I2 is out of the plane.

So, magnetic fields at point P due to wires 1 and 2 are perpendicular to each other.

Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other.

∴A→R,Q

In case (B)

Similarly, as above, →B at P, due to I1

is toward left and due to I2 is into the plane.

So, magnetic fields at point P due to wires 1 and 2 are perpendicular to each other.

Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other.

∴B→R,Q

In case (C)

→B at P, due to I1

is toward right and due to I2 is out of the plane.

So, magnetic fields at point P due to wires 1 and 2 are perpendicular to each other.

Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other.

∴C→R,Q

In case (D)

→B at P, due to I1 and I2 is out of the plane.

So, magnetic fields at point P due to wires 1 and 2 are in the same direction.

Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other.

∴D→S,Q

Hence, option (B) is correct.

In case (A)

Due to I1, →B at P, from right-hand thumb rule, is upward and due to I2 is out of the plane.

So, magnetic fields at point P due to wires 1 and 2 are perpendicular to each other.

Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other.

∴A→R,Q

In case (B)

Similarly, as above, →B at P, due to I1

is toward left and due to I2 is into the plane.

So, magnetic fields at point P due to wires 1 and 2 are perpendicular to each other.

Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other.

∴B→R,Q

In case (C)

→B at P, due to I1

is toward right and due to I2 is out of the plane.

So, magnetic fields at point P due to wires 1 and 2 are perpendicular to each other.

Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other.

∴C→R,Q

In case (D)

→B at P, due to I1 and I2 is out of the plane.

So, magnetic fields at point P due to wires 1 and 2 are in the same direction.

Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other.

∴D→S,Q

Hence, option (B) is correct.

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