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Question

# Match the entries of column I with the entries of column II in the following table. Column I Column II (A) (P) Wires 1 and 2 attract each other. (B) (Q) Wires 1 and 2 do not exert any force on each other. (C) (R) Magnetic fields at point P due to wires 1 and 2 are perpendicular to each other. (D) Wires 1 and 2 are in the same plane without touching each other. (S) Magnetic fields at point P due to wires 1 and 2 are in the same direction. Which of the following option has the correct combination, considering column I and column II?

A
AP,Q
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B
BQ,R
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C
CR,S
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D
DP,R
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Solution

## The correct option is B B→Q,RIn case (A) Due to I1, →B at P, from right-hand thumb rule, is upward and due to I2 is out of the plane. So, magnetic fields at point P due to wires 1 and 2 are perpendicular to each other. Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other. ∴A→R,Q In case (B) Similarly, as above, →B at P, due to I1 is toward left and due to I2 is into the plane. So, magnetic fields at point P due to wires 1 and 2 are perpendicular to each other. Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other. ∴B→R,Q In case (C) →B at P, due to I1 is toward right and due to I2 is out of the plane. So, magnetic fields at point P due to wires 1 and 2 are perpendicular to each other. Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other. ∴C→R,Q In case (D) →B at P, due to I1 and I2 is out of the plane. So, magnetic fields at point P due to wires 1 and 2 are in the same direction. Also, I1⊥I2. So, wires 1 and 2 do not exert any force on each other. ∴D→S,Q Hence, option (B) is correct.

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